Test questions. 1. Voltages V1, V3, V4 in the scheme below equal to ____ respectively.

1. Voltages V₁, V₃, V₄ in the scheme below equal to ________ respectively.

A. 4.3 V, 0, 0 B. 0, 4.3V, 0 C. 4.3 V, 4.3 V, 0 D. 0, 0, 0 E. 4.3 V, 0, 4.3 V

2. How many states has the switch got?

A. 1 B. 2 C. 3 D. 4 E. 5

3. What can you say about state of diodes 1, 2, 3 in the picture?

A. reverse, forward, reverse B. reverse, forward, forward

C. forward, reverse, forward D. Reverse, reverse, forward

E. forward, forward, reverse

4. The second strip to obtain resistance 560 Ω must be

A. blue B. Green C. Brown D. Yellow E. red

5. Value of resistance is 9.6 kΩ. It means that the first three strips on the resistance case (in whole the case has got 4 strips) are:

A. white, blue, red B. gray, brown, black C. Black, brown, green

D. brown, black, brown E. brown, black, red

6. Analyze the information. Fill in the gaps.

Anode voltage is +5V, cathode V is +3V. The diode is ______. Anode voltage is -5V, cathode V is -3V. The diode is ______.

A. ON, ON B. OFF, OFF C. ON, OFF D. OFF, ON E. all answers are wrong

7. Forward bias means that for diode

A. anode voltage is more positive than its cathode one

B. anode voltage is equal to or is more negative than its cathode one

C. anode voltage is positive D. anode voltage is negative E. all answers are wrong

8. For the circuit below if V_A=5V V_B=0V D₀ is _______, D₁ is ______, and LED₀ is________.

A. open, closed, ON B. open, open, ON C. closed, closed, OFF

D. closed, open, ON E. open, open, OFF

9. Calculate current through typical red LED if resistor for its limitation is equal to 330 Ω. Anode voltage of LED is 5V.

A. 10 mA B. 15 mA C. 20 mA D. 25 mA E. 30 mA

10. For the circuit below define current through diode if R=2kΩ

A. 5 mA

B. 4.5 mA

C. 4.3 mA

D. 2.15 mA

E. 0.86 mA

LABORATORY WORK # 2.