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Asynchronous motors of 4A seryes
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| Rated Power Pr, kW | Synchronous rotational speed ns, rpm | ||||||
| Type designation | S, % | Type designation | S, % | Type designation | S, % | ||
| 0, 55 | 63В2 | 8, 5 | 71A4 | 7, 3 | 71B6 | ||
| 0, 75 | 71А2 | 5, 9 | 71B4 | 7, 5 | 80A6 | 8, 4 | |
| 1, 1 | 71В2 | 6, 3 | 80A4 | 5, 4 | 80B6 | 8, 0 | |
| 1, 5 | 80А2 | 4, 2 | 80B4 | 5, 8 | 90L6 | 6, 4 | |
| 2, 2 | 80В2 | 4, 3 | 90L4 | 5, 1 | 100L6 | 5, 1 | |
| 3, 0 | 90L2 | 4, 3 | 100S4 | 4, 4 | 112MA6 | 4, 7 | |
| 4, 0 | 100S2 | 3, 3 | 100L4 | 4, 7 | 112MB6 | 5, 1 | |
| 5, 5 | 100L2 | 3, 4 | 112M4 | 3, 7 | 132S2 | 3, 3 | |
| 7, 5 | 112M2 | 2, 5 | 132S4 | 3, 0 | 132M6 | 3, 2 | |
| 11, 0 | 132M2 | 2, 3 | 132M4 | 2, 8 | 160S6 | 2, 7 | |
| 160S2 | 2, 1 | 160S4 | 2, 3 | 160M6 | 2, 6 | ||
| 18, 5 | 160M2 | 2, 1 | 160M4 | 2, 2 | 180M6 | 2, 7 | |
| 180S2 | 2, 0 | 180S4 | 2, 0 | 200M6 | 2, 8 | ||
| 180M2 | 1, 9 | 180M4 | 1, 9 | 200L6 | 2, 1 |
It is recommended to take asynchronous motors of either synchronous rotational speed ns= 1500 rpm or ns= 1000 rpm for the given mechanical drives.
In our case we select 4A160S6 Induction Motor (Pr = 11 kW, ns = 1000 rpm).
1.4. Determine the motor rated rotational speed nr.
where S is relative speed loss that is determined according to table 1.2. In our case S = 2.7 %. After substituting the corresponding magnitudes we obtain
1.5. Determine the output rotational speed.
1.6. Determine the total velocity ratio of the mechanical drive
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1.7. Distribute the total velocity ratio between mechanical drive steps.
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